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wordpress代码一键获取网站的全部链接

TSY · 6月23日 · 2020年本文共909个字 · 预计阅读4分钟306次已读

使用方法

1.创建个PHP文件,名字随意,(比如:1.php)将9rQCxMP4aMR2A3ZH68MP4I5o1coJzqMZ以下面代码复制到1.php中

9rQCxMP4aMR2A3ZH68MP4I5o1coJzqMZ

2上传至网站根目录,esfrdgrsGSSDXCSFD9rQCxMP4aMR2A3然后访问域名/1.php就可9rQCxMP4aMR2A3ZH68MP4I5o1coJzqMZ以了!

esfrdgrsGSSDXCSFD9rQCxMP4aMR2A3
wordpress代码一键获取网站的全部链接

代码

<?php
require('./wp-blog-header.php');
header("Content-type: text/txt");
header('HTTP/1.1 200 OK');
$posts_to_show = 1000; // 获取文章数量
?>
<?php echo 'http://'.$_SERVER['HTTP_HOST']; ?><?php echo "\n"; ?>
<?php
/* 文章页面 */
header("Content-type: text/txt");
$myposts = get_posts( "numberposts=" . $posts_to_show );
foreach( $myposts as $post ) {
the_permalink();
echo "\n";
}
?>
<?php
/* 单页面 */
$mypages = get_pages();
if(count($mypages) > 0) {
foreach($mypages as $page) {
echo get_page_link($page->ID);
echo "\n";
}
}
?>
<?php
/* 博客分类 */
$terms = get_terms('category', 'orderby=name&hide_empty=0' );
$count = count($terms);
if($count > 0){
foreach ($terms as $term) {
echo get_term_link($term, $term->slug);
echo "\n";
}
}
?>
<?php
/* 标签(可选) */
$tags = get_terms("post_tag");
foreach ( $tags as $key => $tag ) {
$link = get_term_link( intval($tag->term_id), "post_tag" );
if ( is_wp_error( $link ) ) {
return false;
$tags[ $key ]->link = $link;
}
echo $link;
echo "\n";
}
?>
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